Quote:
Originally Posted by

**shadezey** i have 2 problems that i cant seems to wrap my finger around. i would appreciate some help

a) 20lbs of onions r needed. if the yield percentage of the onions is app 85% how much onions must be purchase to get 20%

You mean to get 20lbs? Then your equation, where N is the number of pounds of onions needed to get 20lbs yield:

20 = 85/100 x N

N = 20 x 100/85 = 23.53 lbs

Quote:

Originally Posted by

**shadezey**

b) what is the edible portion of a fish which has a yield percentage of 56.5%. given that the purchase is made each day for a restaurant what is the max # of patrons that can daily order fish in their meals if each patron is served .75kg

750 g fish per person? That's over a pound and a half. Nobody's going to eat that much fish. Nevertheless, the question cannot be answered with the information provided. We would need to know the weight of the fish in order to calculate the max # of patrons that can be served.

If W is the weight of the fish in grams, then N, the number of patrons you can serve, is:

N = W x (56.5/100) / 750